What Are Regular Expressions?
Regular expressions are a way to describe a set of strings based on common characteristics shared by each string in the set. They can be used to search, edit, or manipulate text and data. You must learn a specific syntax to create regular expressions — one that goes beyond the normal syntax of the Java programming language. Regular expressions vary in complexity, but once you understand the basics of how they're constructed, you'll be able to decipher (or create) any regular expression. This trail teaches the regular expression syntax supported by the java.util.regex
API and presents several working examples to illustrate how the various objects interact. In the world of regular expressions, there are many different flavors to choose from, such as grep, Perl, Tcl, Python, PHP, and awk. The regular expression syntax in the java.util.regex
API is most similar to that found in Perl.
How Are Regular Expressions Represented in This Package?
Thejava.util.regex
package primarily consists of three classes: Pattern
, Matcher
, and PatternSyntaxException
.
- A
Pattern
object is a compiled representation of a regular expression. ThePattern
class provides no public constructors. To create a pattern, you must first invoke one of itspublic static compile
methods, which will then return aPattern
object. These methods accept a regular expression as the first argument; the first few lessons of this trail will teach you the required syntax. - A
Matcher
object is the engine that interprets the pattern and performs match operations against an input string. Like thePattern
class,Matcher
defines no public constructors. You obtain aMatcher
object by invoking thematcher
method on aPattern
object. - A
PatternSyntaxException
object is an unchecked exception that indicates a syntax error in a regular expression pattern.
RegexTestHarness.java
, for exploring the regular expression constructs supported by this API. The command to run this code is java RegexTestHarness
; no command-line arguments are accepted. The application loops repeatedly, prompting the user for a regular expression and input string. Using this test harness is optional, but you may find it convenient for exploring the test cases discussed in the following pages.
String Literalsimport java.io.Console;
import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class RegexTestHarness {
public static void main(String[] args){
Console console = System.console();
if (console == null) {
System.err.println("No console.");
System.exit(1);
}
while (true) {
Pattern pattern =
Pattern.compile(console.readLine("%nEnter your regex: "));
Matcher matcher =
pattern.matcher(console.readLine("Enter input string to search: "));
boolean found = false;
while (matcher.find()) {
console.format("I found the text \"%s\" starting at " +
"index %d and ending at index %d.%n",
matcher.group(), matcher.start(), matcher.end());
found = true;
}
if(!found){
console.format("No match found.%n");
}
}
}
}
Before continuing to the next section, save and compile this code to ensure that your development environment supports the required packages.
The most basic form of pattern matching supported by this API is the match of a string literal. For example, if the regular expression is
foo
and the input string is foo
, the match will succeed because the strings are identical. Try this out with the test harness: This match was a success. Note that while the input string is 3 characters long, the start index is 0 and the end index is 3. By convention, ranges are inclusive of the beginning index and exclusive of the end index, as shown in the following figure:
Enter your regex: foo
Enter input string to search: foo
I found the text "foo" starting at index 0 and ending at index 3.
The string literal "foo", with numbered cells and index values.
With subsequent matches, you'll notice some overlap; the start index for the next match is the same as the end index of the previous match:
Enter your regex: foo
Enter input string to search: foofoofoo
I found the text "foo" starting at index 0 and ending at index 3.
I found the text "foo" starting at index 3 and ending at index 6.
I found the text "foo" starting at index 6 and ending at index 9.
Metacharacters
This API also supports a number of special characters that affect the way a pattern is matched. Change the regular expression tocat.
and the input string to cats
. The output will appear as follows: The match still succeeds, even though the dot "Enter your regex: cat.
Enter input string to search: cats
I found the text "cats" starting at index 0 and ending at index 4.
.
" is not present in the input string. It succeeds because the dot is a metacharacter — a character with special meaning interpreted by the matcher. The metacharacter "." means "any character" which is why the match succeeds in this example. The metacharacters supported by this API are: ([{\^-$|]})?*+.
Note: In certain situations the special characters listed above will not be treated as metacharacters. You'll encounter this as you learn more about how regular expressions are constructed. You can, however, use this list to check whether or not a specific character will ever be considered a metacharacter. For example, the characters!
@
and#
never carry a special meaning.
There are two ways to force a metacharacter to be treated as an ordinary character:
- precede the metacharacter with a backslash, or
- enclose it within
\Q
(which starts the quote) and\E
(which ends it).
\Q
and \E
can be placed at any location within the expression, provided that the \Q
comes first.Character Classes
If you browse through the
Pattern
class specification, you'll see tables summarizing the supported regular expression constructs. In the "Character Classes" section you'll find the following: The left-hand column specifies the regular expression constructs, while the right-hand column describes the conditions under which each construct will match.
Character Classes [abc]
a, b, or c (simple class) [^abc]
Any character except a, b, or c (negation) [a-zA-Z]
a through z, or A through Z, inclusive (range) [a-d[m-p]]
a through d, or m through p: [a-dm-p] (union) [a-z&&[def]]
d, e, or f (intersection) [a-z&&[^bc]]
a through z, except for b and c: [ad-z] (subtraction) [a-z&&[^m-p]]
a through z, and not m through p: [a-lq-z] (subtraction)
Note: The word "class" in the phrase "character class" does not refer to a.class
file. In the context of regular expressions, a character class is a set of characters enclosed within square brackets. It specifies the characters that will successfully match a single character from a given input string.
Simple Classes
The most basic form of a character class is to simply place a set of characters side-by-side within square brackets. For example, the regular expression[bcr]at
will match the words "bat", "cat", or "rat" because it defines a character class (accepting either "b", "c", or "r") as its first character.
In the above examples, the overall match succeeds only when the first letter matches one of the characters defined by the character class.
Enter your regex: [bcr]at
Enter input string to search: bat
I found the text "bat" starting at index 0 and ending at index 3.
Enter your regex: [bcr]at
Enter input string to search: cat
I found the text "cat" starting at index 0 and ending at index 3.
Enter your regex: [bcr]at
Enter input string to search: rat
I found the text "rat" starting at index 0 and ending at index 3.
Enter your regex: [bcr]at
Enter input string to search: hat
No match found.
Negation
To match all characters except those listed, insert the "^
" metacharacter at the beginning of the character class. This technique is known as negation. The match is successful only if the first character of the input string does not contain any of the characters defined by the character class.
Enter your regex: [^bcr]at
Enter input string to search: bat
No match found.
Enter your regex: [^bcr]at
Enter input string to search: cat
No match found.
Enter your regex: [^bcr]at
Enter input string to search: rat
No match found.
Enter your regex: [^bcr]at
Enter input string to search: hat
I found the text "hat" starting at index 0 and ending at index 3.
Ranges
Sometimes you'll want to define a character class that includes a range of values, such as the letters "a through h" or the numbers "1 through 5". To specify a range, simply insert the "-
" metacharacter between the first and last character to be matched, such as [1-5]
or [a-h]
. You can also place different ranges beside each other within the class to further expand the match possibilities. For example, [a-zA-Z]
will match any letter of the alphabet: a to z (lowercase) or A to Z (uppercase). Here are some examples of ranges and negation:
Enter your regex: [a-c]
Enter input string to search: a
I found the text "a" starting at index 0 and ending at index 1.
Enter your regex: [a-c]
Enter input string to search: b
I found the text "b" starting at index 0 and ending at index 1.
Enter your regex: [a-c]
Enter input string to search: c
I found the text "c" starting at index 0 and ending at index 1.
Enter your regex: [a-c]
Enter input string to search: d
No match found.
Enter your regex: foo[1-5]
Enter input string to search: foo1
I found the text "foo1" starting at index 0 and ending at index 4.
Enter your regex: foo[1-5]
Enter input string to search: foo5
I found the text "foo5" starting at index 0 and ending at index 4.
Enter your regex: foo[1-5]
Enter input string to search: foo6
No match found.
Enter your regex: foo[^1-5]
Enter input string to search: foo1
No match found.
Enter your regex: foo[^1-5]
Enter input string to search: foo6
I found the text "foo6" starting at index 0 and ending at index 4.
Unions
You can also use unions to create a single character class comprised of two or more separate character classes. To create a union, simply nest one class inside the other, such as[0-4[6-8]]
. This particular union creates a single character class that matches the numbers 0, 1, 2, 3, 4, 6, 7, and 8. Enter your regex: [0-4[6-8]]
Enter input string to search: 0
I found the text "0" starting at index 0 and ending at index 1.
Enter your regex: [0-4[6-8]]
Enter input string to search: 5
No match found.
Enter your regex: [0-4[6-8]]
Enter input string to search: 6
I found the text "6" starting at index 0 and ending at index 1.
Enter your regex: [0-4[6-8]]
Enter input string to search: 8
I found the text "8" starting at index 0 and ending at index 1.
Enter your regex: [0-4[6-8]]
Enter input string to search: 9
No match found.
Intersections
To create a single character class matching only the characters common to all of its nested classes, use&&
, as in [0-9&&[345]]
. This particular intersection creates a single character class matching only the numbers common to both character classes: 3, 4, and 5. And here's an example that shows the intersection of two ranges:
Enter your regex: [0-9&&[345]]
Enter input string to search: 3
I found the text "3" starting at index 0 and ending at index 1.
Enter your regex: [0-9&&[345]]
Enter input string to search: 4
I found the text "4" starting at index 0 and ending at index 1.
Enter your regex: [0-9&&[345]]
Enter input string to search: 5
I found the text "5" starting at index 0 and ending at index 1.
Enter your regex: [0-9&&[345]]
Enter input string to search: 2
No match found.
Enter your regex: [0-9&&[345]]
Enter input string to search: 6
No match found.
Enter your regex: [2-8&&[4-6]]
Enter input string to search: 3
No match found.
Enter your regex: [2-8&&[4-6]]
Enter input string to search: 4
I found the text "4" starting at index 0 and ending at index 1.
Enter your regex: [2-8&&[4-6]]
Enter input string to search: 5
I found the text "5" starting at index 0 and ending at index 1.
Enter your regex: [2-8&&[4-6]]
Enter input string to search: 6
I found the text "6" starting at index 0 and ending at index 1.
Enter your regex: [2-8&&[4-6]]
Enter input string to search: 7
No match found.
Subtraction
Finally, you can use subtraction to negate one or more nested character classes, such as[0-9&&[^345]]
. This example creates a single character class that matches everything from 0 to 9, except the numbers 3, 4, and 5. Now that we've covered how character classes are created, You may want to review the Character Classes table before continuing with the next section.
Enter your regex: [0-9&&[^345]]
Enter input string to search: 2
I found the text "2" starting at index 0 and ending at index 1.
Enter your regex: [0-9&&[^345]]
Enter input string to search: 3
No match found.
Enter your regex: [0-9&&[^345]]
Enter input string to search: 4
No match found.
Enter your regex: [0-9&&[^345]]
Enter input string to search: 5
No match found.
Enter your regex: [0-9&&[^345]]
Enter input string to search: 6
I found the text "6" starting at index 0 and ending at index 1.
Enter your regex: [0-9&&[^345]]
Enter input string to search: 9
I found the text "9" starting at index 0 and ending at index 1.
Pattern
API contains a number of useful predefined character classes, which offer convenient shorthands for commonly used regular expressions: In the table above, each construct in the left-hand column is shorthand for the character class in the right-hand column. For example,
Predefined Character Classes .
Any character (may or may not match line terminators) \d
A digit: [0-9]
\D
A non-digit: [^0-9]
\s
A whitespace character: [ \t\n\x0B\f\r]
\S
A non-whitespace character: [^\s]
\w
A word character: [a-zA-Z_0-9]
\W
A non-word character: [^\w]
\d
means a range of digits (0-9), and \w
means a word character (any lowercase letter, any uppercase letter, the underscore character, or any digit). Use the predefined classes whenever possible. They make your code easier to read and eliminate errors introduced by malformed character classes. Constructs beginning with a backslash are called escaped constructs. We previewed escaped constructs in the String Literals section where we mentioned the use of backslash and \Q
and \E
for quotation. If you are using an escaped construct within a string literal, you must preceed the backslash with another backslash for the string to compile. For example:
In this example
private final String REGEX = "\\d"; // a single digit
\d
is the regular expression; the extra backslash is required for the code to compile. The test harness reads the expressions directly from the Console
, however, so the extra backslash is unnecessary. The following examples demonstrate the use of predefined character classes.
In the first three examples, the regular expression is simply
Enter your regex: .
Enter input string to search: @
I found the text "@" starting at index 0 and ending at index 1.
Enter your regex: .
Enter input string to search: 1
I found the text "1" starting at index 0 and ending at index 1.
Enter your regex: .
Enter input string to search: a
I found the text "a" starting at index 0 and ending at index 1.
Enter your regex: \d
Enter input string to search: 1
I found the text "1" starting at index 0 and ending at index 1.
Enter your regex: \d
Enter input string to search: a
No match found.
Enter your regex: \D
Enter input string to search: 1
No match found.
Enter your regex: \D
Enter input string to search: a
I found the text "a" starting at index 0 and ending at index 1.
Enter your regex: \s
Enter input string to search:
I found the text " " starting at index 0 and ending at index 1.
Enter your regex: \s
Enter input string to search: a
No match found.
Enter your regex: \S
Enter input string to search:
No match found.
Enter your regex: \S
Enter input string to search: a
I found the text "a" starting at index 0 and ending at index 1.
Enter your regex: \w
Enter input string to search: a
I found the text "a" starting at index 0 and ending at index 1.
Enter your regex: \w
Enter input string to search: !
No match found.
Enter your regex: \W
Enter input string to search: a
No match found.
Enter your regex: \W
Enter input string to search: !
I found the text "!" starting at index 0 and ending at index 1.
.
(the "dot" metacharacter) that indicates "any character." Therefore, the match is successful in all three cases (a randomly selected @
character, a digit, and a letter). The remaining examples each use a single regular expression construct from the Predefined Character Classes table. You can refer to this table to figure out the logic behind each match: \d
matches all digits\s
matches spaces\w
matches word characters
\D
matches non-digits\S
matches non-spaces\W
matches non-word characters
Quantifiers allow you to specify the number of occurrences to match against. For convenience, the three sections of the Pattern API specification describing greedy, reluctant, and possessive quantifiers are presented below. At first glance it may appear that the quantifiers
X?
, X??
and X?+
do exactly the same thing, since they all promise to match "X
, once or not at all". There are subtle implementation differences which will be explained near the end of this section.
| Meaning | ||
Greedy | Reluctant | Possessive | |
X? | X?? | X?+ | X , once or not at all |
X* | X*? | X*+ | X , zero or more times |
X+ | X+? | X++ | X , one or more times |
X{n} | X{n}? | X{n}+ | X , exactly n times |
X{n,} | X{n,}? | X{n,}+ | X , at least n times |
X{n,m} | X{n,m}? | X{n,m}+ | X , at least n but not more than m times |
Let's start our look at greedy quantifiers by creating three different regular expressions: the letter "a" followed by either ?
, *
, or +
. Let's see what happens when these expressions are tested against an empty input string ""
:
Enter your regex: a?
Enter input string to search:
I found the text "" starting at index 0 and ending at index 0.
Enter your regex: a*
Enter input string to search:
I found the text "" starting at index 0 and ending at index 0.
Enter your regex: a+
Enter input string to search:
No match found.
Zero-Length Matches
In the above example, the match is successful in the first two cases because the expressionsa?
and a*
both allow for zero occurrences of the letter a
. You'll also notice that the start and end indices are both zero, which is unlike any of the examples we've seen so far. The empty input string ""
has no length, so the test simply matches nothing at index 0. Matches of this sort are known as a zero-length matches. A zero-length match can occur in several cases: in an empty input string, at the beginning of an input string, after the last character of an input string, or in between any two characters of an input string. Zero-length matches are easily identifiable because they always start and end at the same index position. Let's explore zero-length matches with a few more examples. Change the input string to a single letter "a" and you'll notice something interesting:
All three quantifiers found the letter "a", but the first two also found a zero-length match at index 1; that is, after the last character of the input string. Remember, the matcher sees the character "a" as sitting in the cell between index 0 and index 1, and our test harness loops until it can no longer find a match. Depending on the quantifier used, the presence of "nothing" at the index after the last character may or may not trigger a match.
Enter your regex: a?
Enter input string to search: a
I found the text "a" starting at index 0 and ending at index 1.
I found the text "" starting at index 1 and ending at index 1.
Enter your regex: a*
Enter input string to search: a
I found the text "a" starting at index 0 and ending at index 1.
I found the text "" starting at index 1 and ending at index 1.
Enter your regex: a+
Enter input string to search: a
I found the text "a" starting at index 0 and ending at index 1.
Now change the input string to the letter "a" five times in a row and you'll get the following:
The expression
Enter your regex: a?
Enter input string to search: aaaaa
I found the text "a" starting at index 0 and ending at index 1.
I found the text "a" starting at index 1 and ending at index 2.
I found the text "a" starting at index 2 and ending at index 3.
I found the text "a" starting at index 3 and ending at index 4.
I found the text "a" starting at index 4 and ending at index 5.
I found the text "" starting at index 5 and ending at index 5.
Enter your regex: a*
Enter input string to search: aaaaa
I found the text "aaaaa" starting at index 0 and ending at index 5.
I found the text "" starting at index 5 and ending at index 5.
Enter your regex: a+
Enter input string to search: aaaaa
I found the text "aaaaa" starting at index 0 and ending at index 5.
a?
finds an individual match for each character, since it matches when "a" appears zero or one times. The expression a*
finds two separate matches: all of the letter "a"'s in the first match, then the zero-length match after the last character at index 5. And finally, a+
matches all occurrences of the letter "a", ignoring the presence of "nothing" at the last index. At this point, you might be wondering what the results would be if the first two quantifiers encounter a letter other than "a". For example, what happens if it encounters the letter "b", as in "ababaaaab"?
Let's find out:
Even though the letter "b" appears in cells 1, 3, and 8, the output reports a zero-length match at those locations. The regular expression
Enter your regex: a?
Enter input string to search: ababaaaab
I found the text "a" starting at index 0 and ending at index 1.
I found the text "" starting at index 1 and ending at index 1.
I found the text "a" starting at index 2 and ending at index 3.
I found the text "" starting at index 3 and ending at index 3.
I found the text "a" starting at index 4 and ending at index 5.
I found the text "a" starting at index 5 and ending at index 6.
I found the text "a" starting at index 6 and ending at index 7.
I found the text "a" starting at index 7 and ending at index 8.
I found the text "" starting at index 8 and ending at index 8.
I found the text "" starting at index 9 and ending at index 9.
Enter your regex: a*
Enter input string to search: ababaaaab
I found the text "a" starting at index 0 and ending at index 1.
I found the text "" starting at index 1 and ending at index 1.
I found the text "a" starting at index 2 and ending at index 3.
I found the text "" starting at index 3 and ending at index 3.
I found the text "aaaa" starting at index 4 and ending at index 8.
I found the text "" starting at index 8 and ending at index 8.
I found the text "" starting at index 9 and ending at index 9.
Enter your regex: a+
Enter input string to search: ababaaaab
I found the text "a" starting at index 0 and ending at index 1.
I found the text "a" starting at index 2 and ending at index 3.
I found the text "aaaa" starting at index 4 and ending at index 8.
a?
is not specifically looking for the letter "b"; it's merely looking for the presence (or lack thereof) of the letter "a". If the quantifier allows for a match of "a" zero times, anything in the input string that's not an "a" will show up as a zero-length match. The remaining a's are matched according to the rules discussed in the previous examples. To match a pattern exactly n number of times, simply specify the number inside a set of braces:
Here, the regular expression
Enter your regex: a{3}
Enter input string to search: aa
No match found.
Enter your regex: a{3}
Enter input string to search: aaa
I found the text "aaa" starting at index 0 and ending at index 3.
Enter your regex: a{3}
Enter input string to search: aaaa
I found the text "aaa" starting at index 0 and ending at index 3.
a{3}
is searching for three occurrences of the letter "a" in a row. The first test fails because the input string does not have enough a's to match against. The second test contains exactly 3 a's in the input string, which triggers a match. The third test also triggers a match because there are exactly 3 a's at the beginning of the input string. Anything following that is irrelevant to the first match. If the pattern should appear again after that point, it would trigger subsequent matches: To require a pattern to appear at least n times, add a comma after the number:
Enter your regex: a{3}
Enter input string to search: aaaaaaaaa
I found the text "aaa" starting at index 0 and ending at index 3.
I found the text "aaa" starting at index 3 and ending at index 6.
I found the text "aaa" starting at index 6 and ending at index 9.
With the same input string, this test finds only one match, because the 9 a's in a row satisfy the need for "at least" 3 a's.
Enter your regex: a{3,}
Enter input string to search: aaaaaaaaa
I found the text "aaaaaaaaa" starting at index 0 and ending at index 9.
Finally, to specify an upper limit on the number of occurances, add a second number inside the braces:
Here the first match is forced to stop at the upper limit of 6 characters. The second match includes whatever is left over, which happens to be three a's — the mimimum number of characters allowed for this match. If the input string were one character shorter, there would not be a second match since only two a's would remain.
Enter your regex: a{3,6} // find at least 3 (but no more than 6) a's in a row
Enter input string to search: aaaaaaaaa
I found the text "aaaaaa" starting at index 0 and ending at index 6.
I found the text "aaa" starting at index 6 and ending at index 9.
Capturing Groups and Character Classes with Quantifiers
Until now, we've only tested quantifiers on input strings containing one character. In fact, quantifiers can only attach to one character at a time, so the regular expression "abc+" would mean "a, followed by b, followed by c one or more times". It would not mean "abc" one or more times. However, quantifiers can also attach to Character Classes and Capturing Groups, such as[abc]+
(a or b or c, one or more times) or (abc)+
(the group "abc", one or more times). Let's illustrate by specifying the group (dog)
, three times in a row.
Here the first example finds three matches, since the quantifier applies to the entire capturing group. Remove the parentheses, however, and the match fails because the quantifier
Enter your regex: (dog){3}
Enter input string to search: dogdogdogdogdogdog
I found the text "dogdogdog" starting at index 0 and ending at index 9.
I found the text "dogdogdog" starting at index 9 and ending at index 18.
Enter your regex: dog{3}
Enter input string to search: dogdogdogdogdogdog
No match found.
{3}
now applies only to the letter "g". Similarly, we can apply a quantifier to an entire character class:
Here the quantifierEnter your regex: [abc]{3}
Enter input string to search: abccabaaaccbbbc
I found the text "abc" starting at index 0 and ending at index 3.
I found the text "cab" starting at index 3 and ending at index 6.
I found the text "aaa" starting at index 6 and ending at index 9.
I found the text "ccb" starting at index 9 and ending at index 12.
I found the text "bbc" starting at index 12 and ending at index 15.
Enter your regex: abc{3}
Enter input string to search: abccabaaaccbbbc
No match found.
{3}
applies to the entire character class in the first example, but only to the letter "c" in the second. Differences Among Greedy, Reluctant, and Possessive Quantifiers
There are subtle differences among greedy, reluctant, and possessive quantifiers.Greedy quantifiers are considered "greedy" because they force the matcher to read in, or eat, the entire input string prior to attempting the first match. If the first match attempt (the entire input string) fails, the matcher backs off the input string by one character and tries again, repeating the process until a match is found or there are no more characters left to back off from. Depending on the quantifier used in the expression, the last thing it will try matching against is 1 or 0 characters.
The reluctant quantifiers, however, take the opposite approach: They start at the beginning of the input string, then reluctantly eat one character at a time looking for a match. The last thing they try is the entire input string.
Finally, the possessive quantifiers always eat the entire input string, trying once (and only once) for a match. Unlike the greedy quantifiers, possessive quantifiers never back off, even if doing so would allow the overall match to succeed.
To illustrate, consider the input string xfooxxxxxxfoo
.
The first example uses the greedy quantifier
Enter your regex: .*foo // greedy quantifier
Enter input string to search: xfooxxxxxxfoo
I found the text "xfooxxxxxxfoo" starting at index 0 and ending at index 13.
Enter your regex: .*?foo // reluctant quantifier
Enter input string to search: xfooxxxxxxfoo
I found the text "xfoo" starting at index 0 and ending at index 4.
I found the text "xxxxxxfoo" starting at index 4 and ending at index 13.
Enter your regex: .*+foo // possessive quantifier
Enter input string to search: xfooxxxxxxfoo
No match found.
.*
to find "anything", zero or more times, followed by the letters "f" "o" "o"
. Because the quantifier is greedy, the .*
portion of the expression first eats the entire input string. At this point, the overall expression cannot succeed, because the last three letters ("f" "o" "o"
) have already been consumed. So the matcher slowly backs off one letter at a time until the rightmost occurrence of "foo" has been regurgitated, at which point the match succeeds and the search ends. The second example, however, is reluctant, so it starts by first consuming "nothing". Because "foo" doesn't appear at the beginning of the string, it's forced to swallow the first letter (an "x"), which triggers the first match at 0 and 4. Our test harness continues the process until the input string is exhausted. It finds another match at 4 and 13.
The third example fails to find a match because the quantifier is possessive. In this case, the entire input string is consumed by .*+
, leaving nothing left over to satisfy the "foo" at the end of the expression. Use a possessive quantifier for situations where you want to seize all of something without ever backing off; it will outperform the equivalent greedy quantifier in cases where the match is not immediately found.
In the previous section, we saw how quantifiers attach to one character, character class, or capturing group at a time. But until now, we have not discussed the notion of capturing groups in any detail.
Capturing groups are a way to treat multiple characters as a single unit. They are created by placing the characters to be grouped inside a set of parentheses. For example, the regular expression (dog)
creates a single group containing the letters "d" "o"
and "g"
. The portion of the input string that matches the capturing group will be saved in memory for later recall via backreferences (as discussed below in the section, Backreferences).
Numbering
As described in thePattern
API, capturing groups are numbered by counting their opening parentheses from left to right. In the expression ((A)(B(C)))
, for example, there are four such groups: ((A)(B(C)))
(A)
(B(C))
(C)
groupCount
method on a matcher object. The groupCount
method returns an int
showing the number of capturing groups present in the matcher's pattern. In this example, groupCount
would return the number 4
, showing that the pattern contains 4 capturing groups. There is also a special group, group 0, which always represents the entire expression. This group is not included in the total reported by groupCount
. Groups beginning with (?
are pure, non-capturing groups that do not capture text and do not count towards the group total. (You'll see examples of non-capturing groups later in the section Methods of the Pattern Class.)
It's important to understand how groups are numbered because some Matcher
methods accept an int
specifying a particular group number as a parameter:
-
public int start(int group)
: Returns the start index of the subsequence captured by the given group during the previous match operation. -
public int end (int group)
: Returns the index of the last character, plus one, of the subsequence captured by the given group during the previous match operation. -
public String group (int group)
: Returns the input subsequence captured by the given group during the previous match operation.
Backreferences
The section of the input string matching the capturing group(s) is saved in memory for later recall via backreference. A backreference is specified in the regular expression as a backslash (\
) followed by a digit indicating the number of the group to be recalled. For example, the expression (\d\d)
defines one capturing group matching two digits in a row, which can be recalled later in the expression via the backreference \1
. To match any 2 digits, followed by the exact same two digits, you would use (\d\d)\1
as the regular expression:
If you change the last two digits the match will fail:
Enter your regex: (\d\d)\1
Enter input string to search: 1212
I found the text "1212" starting at index 0 and ending at index 4.
For nested capturing groups, backreferencing works in exactly the same way: Specify a backslash followed by the number of the group to be recalled.
Enter your regex: (\d\d)\1
Enter input string to search: 1234
No match found.
You can make your pattern matches more precise by specifying such information with boundary matchers. For example, maybe you're interested in finding a particular word, but only if it appears at the beginning or end of a line. Or maybe you want to know if the match is taking place on a word boundary, or at the end of the previous match.
The following table lists and explains all the boundary matchers.
The following examples demonstrate the use of boundary matchers
Boundary Matchers ^
The beginning of a line $
The end of a line \b
A word boundary \B
A non-word boundary \A
The beginning of the input \G
The end of the previous match \Z
The end of the input but for the final terminator, if any \z
The end of the input
^
and $
. As noted above, ^
matches the beginning of a line, and $
matches the end. The first example is successful because the pattern occupies the entire input string. The second example fails because the input string contains extra whitespace at the beginning. The third example specifies an expression that allows for unlimited white space, followed by "dog" on the end of the line. The fourth example requires "dog" to be present at the beginning of a line followed by an unlimited number of word characters.
Enter your regex: ^dog$
Enter input string to search: dog
I found the text "dog" starting at index 0 and ending at index 3.
Enter your regex: ^dog$
Enter input string to search: dog
No match found.
Enter your regex: \s*dog$
Enter input string to search: dog
I found the text " dog" starting at index 0 and ending at index 15.
Enter your regex: ^dog\w*
Enter input string to search: dogblahblah
I found the text "dogblahblah" starting at index 0 and ending at index 11.
To check if a pattern begins and ends on a word boundary (as opposed to a substring within a longer string), just use \b
on either side; for example, \bdog\b
To match the expression on a non-word boundary, use
Enter your regex: \bdog\b
Enter input string to search: The dog plays in the yard.
I found the text "dog" starting at index 4 and ending at index 7.
Enter your regex: \bdog\b
Enter input string to search: The doggie plays in the yard.
No match found.
\B
instead: To require the match to occur only at the end of the previous match, use
Enter your regex: \bdog\B
Enter input string to search: The dog plays in the yard.
No match found.
Enter your regex: \bdog\B
Enter input string to search: The doggie plays in the yard.
I found the text "dog" starting at index 4 and ending at index 7.
\G
: Here the second example finds only one match, because the second occurrence of "dog" does not start at the end of the previous match.
Enter your regex: dog
Enter input string to search: dog dog
I found the text "dog" starting at index 0 and ending at index 3.
I found the text "dog" starting at index 4 and ending at index 7.
Enter your regex: \Gdog
Enter input string to search: dog dog
I found the text "dog" starting at index 0 and ending at index 3.
Pattern
objects in their most basic form. This section explores advanced techniques such as creating patterns with flags and using embedded flag expressions. It also explores some additional useful methods that we haven't yet discussed. Creating a Pattern with Flags
ThePattern
class defines an alternate compile
method that accepts a set of flags affecting the way the pattern is matched. The flags parameter is a bit mask that may include any of the following public static fields: -
Pattern.CANON_EQ
Enables canonical equivalence. When this flag is specified, two characters will be considered to match if, and only if, their full canonical decompositions match. The expression"a\u030A"
, for example, will match the string"\u00E5"
when this flag is specified. By default, matching does not take canonical equivalence into account. Specifying this flag may impose a performance penalty. -
Pattern.CASE_INSENSITIVE
Enables case-insensitive matching. By default, case-insensitive matching assumes that only characters in the US-ASCII charset are being matched. Unicode-aware case-insensitive matching can be enabled by specifying the UNICODE_CASE flag in conjunction with this flag. Case-insensitive matching can also be enabled via the embedded flag expression(?i)
. Specifying this flag may impose a slight performance penalty. -
Pattern.COMMENTS
Permits whitespace and comments in the pattern. In this mode, whitespace is ignored, and embedded comments starting with#
are ignored until the end of a line. Comments mode can also be enabled via the embedded flag expression(?x)
. -
Pattern.DOTALL
Enables dotall mode. In dotall mode, the expression.
matches any character, including a line terminator. By default this expression does not match line terminators. Dotall mode can also be enabled via the embedded flag expression(?s)
. (The s is a mnemonic for "single-line" mode, which is what this is called in Perl.) -
Pattern.LITERAL
Enables literal parsing of the pattern. When this flag is specified then the input string that specifies the pattern is treated as a sequence of literal characters. Metacharacters or escape sequences in the input sequence will be given no special meaning. The flagsCASE_INSENSITIVE
andUNICODE_CASE
retain their impact on matching when used in conjunction with this flag. The other flags become superfluous. There is no embedded flag character for enabling literal parsing. -
Pattern.MULTILINE
Enables multiline mode. In multiline mode the expressions^
and$
match just after or just before, respectively, a line terminator or the end of the input sequence. By default these expressions only match at the beginning and the end of the entire input sequence. Multiline mode can also be enabled via the embedded flag expression(?m)
. -
Pattern.UNICODE_CASE
Enables Unicode-aware case folding. When this flag is specified then case-insensitive matching, when enabled by theCASE_INSENSITIVE
flag, is done in a manner consistent with the Unicode Standard. By default, case-insensitive matching assumes that only characters in the US-ASCII charset are being matched. Unicode-aware case folding can also be enabled via the embedded flag expression(?u)
. Specifying this flag may impose a performance penalty. -
Pattern.UNIX_LINES
Enables Unix lines mode. In this mode, only the'\n'
line terminator is recognized in the behavior of.
,^
, and$
. Unix lines mode can also be enabled via the embedded flag expression(?d)
.
RegexTestHarness.java
to create a pattern with case-insensitive matching. First, modify the code to invoke the alternate version of compile
:
Then compile and run the test harness to get the following results:Pattern pattern =
Pattern.compile(console.readLine("%nEnter your regex: "),
Pattern.CASE_INSENSITIVE);
As you can see, the string literal "dog" matches both occurences, regardless of case. To compile a pattern with multiple flags, separate the flags to be included using the bitwise OR operator "
Enter your regex: dog
Enter input string to search: DoGDOg
I found the text "DoG" starting at index 0 and ending at index 3.
I found the text "DOg" starting at index 3 and ending at index 6.
|
". For clarity, the following code samples hardcode the regular expression instead of reading it from the Console
: You could also specify an
pattern = Pattern.compile("[az]$", Pattern.MULTILINE | Pattern.UNIX_LINES);
int
variable instead:
final int flags = Pattern.CASE_INSENSITIVE | Pattern.UNICODE_CASE;
Pattern pattern = Pattern.compile("aa", flags);
Embedded Flag Expressions
It's also possible to enable various flags using embedded flag expressions. Embedded flag expressions are an alternative to the two-argument version ofcompile
, and are specified in the regular expression itself. The following example uses the original test harness, RegexTestHarness.java
with the embedded flag expression (?i)
to enable case-insensitive matching. Once again, all matches succeed regardless of case.
Enter your regex: (?i)foo
Enter input string to search: FOOfooFoOfoO
I found the text "FOO" starting at index 0 and ending at index 3.
I found the text "foo" starting at index 3 and ending at index 6.
I found the text "FoO" starting at index 6 and ending at index 9.
I found the text "foO" starting at index 9 and ending at index 12.
The embedded flag expressions that correspond to Pattern
's publicly accessible fields are presented in the following table:
Constant Equivalent Embedded Flag Expression Pattern.CANON_EQ
None Pattern.CASE_INSENSITIVE
(?i)
Pattern.COMMENTS
(?x)
Pattern.MULTILINE
(?m)
Pattern.DOTALL
(?s)
Pattern.LITERAL
None Pattern.UNICODE_CASE
(?u)
Pattern.UNIX_LINES
(?d)
Using the matches(String,CharSequence)
Method
The Pattern
class defines a convenient matches
method that allows you to quickly check if a pattern is present in a given input string. As with all public static methods, you should invoke matches
by its class name, such as Pattern.matches("\\d","1");
. In this example, the method returns true
, because the digit "1" matches the regular expression \d
. Using the split(String)
Method
The split
method is a great tool for gathering the text that lies on either side of the pattern that's been matched. As shown below in SplitDemo.java
, the split
method could extract the words "one two three four five
" from the string "one:two:three:four:five
": import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class SplitDemo {
private static final String REGEX = ":";
private static final String INPUT = "one:two:three:four:five";
public static void main(String[] args) {
Pattern p = Pattern.compile(REGEX);
String[] items = p.split(INPUT);
for(String s : items) {
System.out.println(s);
}
}
}
For simplicity, we've matched a string literal, the colon (OUTPUT:
one
two
three
four
five
:
) instead of a complex regular expression. Since we're still using Pattern
and Matcher
objects, you can use split to get the text that falls on either side of any regular expression. Here's the same example, SplitDemo2.java
, modified to split on digits instead: import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class SplitDemo2 {
private static final String REGEX = "\\d";
private static final String INPUT = "one9two4three7four1five";
public static void main(String[] args) {
Pattern p = Pattern.compile(REGEX);
String[] items = p.split(INPUT);
for(String s : items) {
System.out.println(s);
}
}
}
OUTPUT:
one
two
three
four
five
Other Utility Methods
You may find the following methods to be of some use as well:-
public static String quote(String s)
Returns a literal patternString
for the specifiedString
. This method produces aString
that can be used to create aPattern
that would matchString s
as if it were a literal pattern. Metacharacters or escape sequences in the input sequence will be given no special meaning. -
public String toString()
Returns theString
representation of this pattern. This is the regular expression from which this pattern was compiled.
Pattern Method Equivalents in java.lang.String
Regular expression support also exists in java.lang.String
through several methods that mimic the behavior of java.util.regex.Pattern
. For convenience, key excerpts from their API are presented below. -
public boolean matches(String regex)
: Tells whether or not this string matches the given regular expression. An invocation of this method of the formstr.matches(regex)
yields exactly the same result as the expressionPattern.matches(regex, str)
. -
public String[] split(String regex, int limit)
: Splits this string around matches of the given regular expression. An invocation of this method of the formstr.split(regex, n)
yields the same result as the expressionPattern.compile(regex).split(str, n)
-
public String[] split(String regex)
: Splits this string around matches of the given regular expression. This method works the same as if you invoked the two-argument split method with the given expression and a limit argument of zero. Trailing empty strings are not included in the resulting array.
CharSequence
with another: -
public String replace(CharSequence target,CharSequence replacement)
: Replaces each substring of this string that matches the literal target sequence with the specified literal replacement sequence. The replacement proceeds from the beginning of the string to the end, for example, replacing "aa" with "b" in the string "aaa" will result in "ba" rather than "ab".
Matcher
class. For convenience, the methods listed below are grouped according to functionality. Index Methods
Index methods provide useful index values that show precisely where the match was found in the input string:-
public int start()
: Returns the start index of the previous match. -
public int start(int group)
: Returns the start index of the subsequence captured by the given group during the previous match operation. -
public int end()
: Returns the offset after the last character matched. -
public int end(int group)
: Returns the offset after the last character of the subsequence captured by the given group during the previous match operation.
Study Methods
Study methods review the input string and return a boolean indicating whether or not the pattern is found.-
public boolean lookingAt()
: Attempts to match the input sequence, starting at the beginning of the region, against the pattern. -
public boolean find()
: Attempts to find the next subsequence of the input sequence that matches the pattern. -
public boolean find(int start)
: Resets this matcher and then attempts to find the next subsequence of the input sequence that matches the pattern, starting at the specified index. -
public boolean matches()
: Attempts to match the entire region against the pattern.
Replacement Methods
Replacement methods are useful methods for replacing text in an input string.-
public Matcher appendReplacement(StringBuffer sb, String replacement)
: Implements a non-terminal append-and-replace step. -
public StringBuffer appendTail(StringBuffer sb)
: Implements a terminal append-and-replace step. -
public String replaceAll(String replacement)
: Replaces every subsequence of the input sequence that matches the pattern with the given replacement string. -
public String replaceFirst(String replacement)
: Replaces the first subsequence of the input sequence that matches the pattern with the given replacement string. -
public static String quoteReplacement(String s)
: Returns a literal replacementString
for the specifiedString
. This method produces aString
that will work as a literal replacements
in theappendReplacement
method of theMatcher
class. TheString
produced will match the sequence of characters ins
treated as a literal sequence. Slashes ('\'
) and dollar signs ('$'
) will be given no special meaning.
Using the start
and end
Methods
Here's an example, MatcherDemo.java
, that counts the number of times the word "dog" appears in the input string. import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class MatcherDemo {
private static final String REGEX = "\\bdog\\b";
private static final String INPUT = "dog dog dog doggie dogg";
public static void main(String[] args) {
Pattern p = Pattern.compile(REGEX);
Matcher m = p.matcher(INPUT); // get a matcher object
int count = 0;
while(m.find()) {
count++;
System.out.println("Match number "+count);
System.out.println("start(): "+m.start());
System.out.println("end(): "+m.end());
}
}
}
You can see that this example uses word boundaries to ensure that the lettersOUTPUT:
Match number 1
start(): 0
end(): 3
Match number 2
start(): 4
end(): 7
Match number 3
start(): 8
end(): 11
"d" "o" "g"
are not merely a substring in a longer word. It also gives some useful information about where in the input string the match has occurred. The start
method returns the start index of the subsequence captured by the given group during the previous match operation, and end
returns the index of the last character matched, plus one. Using the matches
and lookingAt
Methods
The matches
and lookingAt
methods both attempt to match an input sequence against a pattern. The difference, however, is that matches
requires the entire input sequence to be matched, while lookingAt
does not. Both methods always start at the beginning of the input string. Here's the full code, MatchesLooking.java
: import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class MatchesLooking {
private static final String REGEX = "foo";
private static final String INPUT = "fooooooooooooooooo";
private static Pattern pattern;
private static Matcher matcher;
public static void main(String[] args) {
// Initialize
pattern = Pattern.compile(REGEX);
matcher = pattern.matcher(INPUT);
System.out.println("Current REGEX is: "+REGEX);
System.out.println("Current INPUT is: "+INPUT);
System.out.println("lookingAt(): "+matcher.lookingAt());
System.out.println("matches(): "+matcher.matches());
}
}
Current REGEX is: foo
Current INPUT is: fooooooooooooooooo
lookingAt(): true
matches(): false
Using replaceFirst(String)
and replaceAll(String)
The replaceFirst
and replaceAll
methods replace text that matches a given regular expression. As their names indicate, replaceFirst
replaces the first occurrence, and replaceAll
replaces all occurences. Here's the ReplaceDemo.java
code: import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class ReplaceDemo {
private static String REGEX = "dog";
private static String INPUT = "The dog says meow. All dogs say meow.";
private static String REPLACE = "cat";
public static void main(String[] args) {
Pattern p = Pattern.compile(REGEX);
Matcher m = p.matcher(INPUT); // get a matcher object
INPUT = m.replaceAll(REPLACE);
System.out.println(INPUT);
}
}
In this first version, all occurrences ofOUTPUT: The cat says meow. All cats say meow.
dog
are replaced with cat
. But why stop here? Rather than replace a simple literal like dog
, you can replace text that matches any regular expression. The API for this method states that "given the regular expression a*b
, the input aabfooaabfooabfoob
, and the replacement string -
, an invocation of this method on a matcher for that expression would yield the string -foo-foo-foo-
." Here's the ReplaceDemo2.java
code:
import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class ReplaceDemo2 {
private static String REGEX = "a*b";
private static String INPUT = "aabfooaabfooabfoob";
private static String REPLACE = "-";
public static void main(String[] args) {
Pattern p = Pattern.compile(REGEX);
Matcher m = p.matcher(INPUT); // get a matcher object
INPUT = m.replaceAll(REPLACE);
System.out.println(INPUT);
}
}
To replace only the first occurrence of the pattern, simply callOUTPUT: -foo-foo-foo-
replaceFirst
instead of replaceAll
. It accepts the same parameter. Using appendReplacement(StringBuffer,String)
and appendTail(StringBuffer)
The Matcher
class also provides appendReplacement
and appendTail
methods for text replacement. The following example, RegexDemo.java
, uses these two methods to achieve the same effect as replaceAll
.
import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class RegexDemo {
private static String REGEX = "a*b";
private static String INPUT = "aabfooaabfooabfoob";
private static String REPLACE = "-";
public static void main(String[] args) {
Pattern p = Pattern.compile(REGEX);
Matcher m = p.matcher(INPUT); // get a matcher object
StringBuffer sb = new StringBuffer();
while(m.find()){
m.appendReplacement(sb,REPLACE);
}
m.appendTail(sb);
System.out.println(sb.toString());
}
}
OUTPUT: -foo-foo-foo-
Matcher Method Equivalents in java.lang.String
For convenience, the String
class mimics a couple of Matcher
methods as well: -
public String replaceFirst(String regex, String replacement)
: Replaces the first substring of this string that matches the given regular expression with the given replacement. An invocation of this method of the formstr.replaceFirst(regex, repl)
yields exactly the same result as the expressionPattern.compile(regex).matcher(str).replaceFirst(repl)
-
public String replaceAll(String regex, String replacement)
: Replaces each substring of this string that matches the given regular expression with the given replacement. An invocation of this method of the formstr.replaceAll(regex, repl)
yields exactly the same result as the expressionPattern.compile(regex).matcher(str).replaceAll(repl)
PatternSyntaxException
is an unchecked exception that indicates a syntax error in a regular expression pattern. The PatternSyntaxException
class provides the following methods to help you determine what went wrong: -
public String getDescription()
: Retrieves the description of the error. -
public int getIndex()
: Retrieves the error index. -
public String getPattern()
: Retrieves the erroneous regular expression pattern. -
public String getMessage()
: Returns a multi-line string containing the description of the syntax error and its index, the erroneous regular-expression pattern, and a visual indication of the error index within the pattern.
RegexTestHarness2.java
, updates our test harness to check for malformed regular expressions: To run this test, enterimport java.io.Console;
import java.util.regex.Pattern;
import java.util.regex.Matcher;
import java.util.regex.PatternSyntaxException;
public class RegexTestHarness2 {
public static void main(String[] args){
Pattern pattern = null;
Matcher matcher = null;
Console console = System.console();
if (console == null) {
System.err.println("No console.");
System.exit(1);
}
while (true) {
try{
pattern =
Pattern.compile(console.readLine("%nEnter your regex: "));
matcher =
pattern.matcher(console.readLine("Enter input string to search: "));
}
catch(PatternSyntaxException pse){
console.format("There is a problem with the regular expression!%n");
console.format("The pattern in question is: %s%n",pse.getPattern());
console.format("The description is: %s%n",pse.getDescription());
console.format("The message is: %s%n",pse.getMessage());
console.format("The index is: %s%n",pse.getIndex());
System.exit(0);
}
boolean found = false;
while (matcher.find()) {
console.format("I found the text \"%s\" starting at " +
"index %d and ending at index %d.%n",
matcher.group(), matcher.start(), matcher.end());
found = true;
}
if(!found){
console.format("No match found.%n");
}
}
}
}
?i)foo
as the regular expression. This mistake is a common scenario in which the programmer has forgotten the opening parenthesis in the embedded flag expression (?i)
. Doing so will produce the following results: From this output, we can see that the syntax error is a dangling metacharacter (the question mark) at index 0. A missing opening parenthesis is the culprit.Enter your regex: ?i)
There is a problem with the regular expression!
The pattern in question is: ?i)
The description is: Dangling meta character '?'
The message is: Dangling meta character '?' near index 0
?i)
^
The index is: 0
Now that you've completed this lesson on regular expressions, you'll probably find that your main references will be the API documentation for the following classes:Pattern
,Matcher
, andPatternSyntaxException
.For a more precise description of the behavior of regular expression constructs, we recommend reading the book Mastering Regular Expressions by Jeffrey E. F. Friedl.
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